1.To fetch ALTERNATE records from a table. (EVEN NUMBERED)
select * from emp where rowid in (select decode(mod(rownum,2),0,rowid, null) from emp);
2.To select ALTERNATE records from a table. (ODD NUMBERED)
select * from emp where rowid in (select decode(mod(rownum,2),0,null ,rowid) from emp);
3.Find the 3rd MAX salary in the emp table.
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);
4.Find the 3rd MIN salary in the emp table.
select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2where e1.sal >= e2.sal);
5.Select FIRST n records from a table.
select * from emp where rownum <= &n;
6.Select LAST n records from a table
select * from emp minus select * from emp where rownum <= (select count(*) - &n from emp);
7.List dept no., Dept name for all the departments in which there are no employees in the department.
select * from dept where deptno not in (select deptno from emp);
alternate solution: select * from dept a where not exists (select * from emp b where a.deptno = b.deptno);
altertnate solution: select empno,ename,b.deptno,dname from emp a, dept b where a.deptno(+) = b.deptno and empno is null;
8.How to get 3 Max salaries ?
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc;
9.How to get 3 Min salaries ?
select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal >= b.sal);
10.How to get nth max salaries ?
select distinct hiredate from emp a where &n = (select count(distinct sal) from emp b where a.sal >= b.sal);
11.Select DISTINCT RECORDS from emp table.
select * from emp a where rowid = (select max(rowid) from emp b where a.empno=b.empno);
12.How to delete duplicate rows in a table?
delete from emp a where rowid != (select max(rowid) from emp b where a.empno=b.empno);
13.Count of number of employees in department wise.
select count(EMPNO), b.deptno, dname from emp a, dept b where a.deptno(+)=b.deptno group by b.deptno,dname;
14. Suppose there is annual salary information provided by emp table. How to fetch monthly salary of each and every employee?
select ename,sal/12 as monthlysal from emp;
15.Select all record from emp table where deptno =10 or 40.
select * from emp where deptno=30 or deptno=10;
16.Select all record from emp table where deptno=30 and sal>1500.
select * from emp where deptno=30 and sal>1500;
17.Select all record from emp where job not in SALESMAN or CLERK.
select * from emp where job not in ('SALESMAN','CLERK');
18.Select all record from emp where ename in 'BLAKE','SCOTT','KING'and'FORD'.
select * from emp where ename in('JONES','BLAKE','SCOTT','KING','FORD');
19.Select all records where ename starts with ‘S’ and its lenth is 6 char.
select * from emp where ename like'S____';
20.Select all records where ename may be any no of character but it should end with ‘R’.
select * from emp where ename like'%R';
21.Count MGR and their salary in emp table.
select count(MGR),count(sal) from emp;
22.In emp table add comm+sal as total sal .
select ename,(sal+nvl(comm,0)) as totalsal from emp;
23.Select any salary <3000 from emp table.
select * from emp where sal> any(select sal from emp where sal<3000);
24.Select all salary <3000 from emp table.
select * from emp where sal> all(select sal from emp where sal<3000);
25.Select all the employee group by deptno and sal in descending order.
select ename,deptno,sal from emp order by deptno,sal desc;
26.How can I create an empty table emp1 with same structure as emp?
Create table emp1 as select * from emp where 1=2;
27.How to retrive record where sal between 1000 to 2000?
Select * from emp where sal>=1000 And sal<2000
28.Select all records where dept no of both emp and dept table matches.
select * from emp where exists(select * from dept where emp.deptno=dept.deptno)
29.If there are two tables emp1 and emp2, and both have common record. How can I fetch all the recods but common records only once?
(Select * from emp) Union (Select * from emp1)
30.How to fetch only common records from two tables emp and emp1?
(Select * from emp) Intersect (Select * from emp1)
31. How can I retrive all records of emp1 those should not present in emp2?
(Select * from emp) Minus (Select * from emp1)
32.Count the totalsa deptno wise where more than 2 employees exist.
SELECT deptno, sum(sal) As totalsal
FROM emp
GROUP BY deptno
HAVING COUNT(empno) > 2
