These questions are the most frequently asked in interviews.

select * from emp where rowid in (select decode(mod(rownum,2),0,rowid, null) from emp);

select * from emp where rowid in (select decode(mod(rownum,2),0,null ,rowid) from emp);

select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);

select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2where e1.sal >= e2.sal);

select * from emp where rownum <= &n;

select * from emp minus select * from emp where rownum <= (select count(*) - &n from emp);

select * from dept where deptno not in (select deptno from emp);

alternate solution: select * from dept a where not exists (select * from emp b where a.deptno = b.deptno);

altertnate solution: select empno,ename,b.deptno,dname from emp a, dept b where a.deptno(+) = b.deptno and empno is null;

select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc;

select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal >= b.sal);

select distinct hiredate from emp a where &n = (select count(distinct sal) from emp b where a.sal >= b.sal);

select * from emp a where rowid = (select max(rowid) from emp b where a.empno=b.empno);

delete from emp a where rowid != (select max(rowid) from emp b where a.empno=b.empno);

select count(EMPNO), b.deptno, dname from emp a, dept b where a.deptno(+)=b.deptno group by b.deptno,dname;

select ename,sal/12 as monthlysal from emp;

select * from emp where deptno=30 or deptno=10;

select * from emp where deptno=30 and sal>1500;

select * from emp where job not in ('SALESMAN','CLERK');

select * from emp where ename in('JONES','BLAKE','SCOTT','KING','FORD');

select * from emp where ename like'S____';

select * from emp where ename like'%R';

select count(MGR),count(sal) from emp;

select ename,(sal+nvl(comm,0)) as totalsal from emp;

select * from emp where sal> any(select sal from emp where sal<3000);

select * from emp where sal> all(select sal from emp where sal<3000);

select ename,deptno,sal from emp order by deptno,sal desc;

Create table emp1 as select * from emp where 1=2;

Select * from emp where sal>=1000 And sal<2000

select * from emp where exists(select * from dept where emp.deptno=dept.deptno)

(Select * from emp) Union (Select * from emp1)

(Select * from emp) Intersect (Select * from emp1)

(Select * from emp) Minus (Select * from emp1)

SELECT deptno, sum(sal) As totalsal

FROM emp

GROUP BY deptno

HAVING COUNT(empno) > 2

**1.To fetch ALTERNATE records from a table. (EVEN NUMBERED)**select * from emp where rowid in (select decode(mod(rownum,2),0,rowid, null) from emp);

**2.To select ALTERNATE records from a table. (ODD NUMBERED)**select * from emp where rowid in (select decode(mod(rownum,2),0,null ,rowid) from emp);

**3.Find the 3rd MAX salary in the emp table.**select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);

**4.Find the 3rd MIN salary in the emp table.**select distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2where e1.sal >= e2.sal);

**5.Select FIRST n records from a table.**select * from emp where rownum <= &n;

**6.Select LAST n records from a table**select * from emp minus select * from emp where rownum <= (select count(*) - &n from emp);

**7.List dept no., Dept name for all the departments in which there are no employees in the department.**select * from dept where deptno not in (select deptno from emp);

alternate solution: select * from dept a where not exists (select * from emp b where a.deptno = b.deptno);

altertnate solution: select empno,ename,b.deptno,dname from emp a, dept b where a.deptno(+) = b.deptno and empno is null;

**8.How to get 3 Max salaries ?**select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc;

**9.How to get 3 Min salaries ?**select distinct sal from emp a where 3 >= (select count(distinct sal) from emp b where a.sal >= b.sal);

**10.How to get nth max salaries ?**select distinct hiredate from emp a where &n = (select count(distinct sal) from emp b where a.sal >= b.sal);

**11.Select DISTINCT RECORDS from emp table.**select * from emp a where rowid = (select max(rowid) from emp b where a.empno=b.empno);

**12.How to delete duplicate rows in a table?**delete from emp a where rowid != (select max(rowid) from emp b where a.empno=b.empno);

**13.Count of number of employees in department wise.**select count(EMPNO), b.deptno, dname from emp a, dept b where a.deptno(+)=b.deptno group by b.deptno,dname;

**14. Suppose there is annual salary information provided by emp table. How to fetch monthly salary of each and every employee?**select ename,sal/12 as monthlysal from emp;

**15.Select all record from emp table where deptno =10 or 40.**select * from emp where deptno=30 or deptno=10;

**16.Select all record from emp table where deptno=30 and sal>1500.**select * from emp where deptno=30 and sal>1500;

**17.Select all record from emp where job not in SALESMAN or CLERK.**select * from emp where job not in ('SALESMAN','CLERK');

**18.Select all record from emp where ename in 'BLAKE','SCOTT','KING'and'FORD'.**select * from emp where ename in('JONES','BLAKE','SCOTT','KING','FORD');

**19.Select all records where ename starts with ‘S’ and its lenth is 6 char.**select * from emp where ename like'S____';

**20.Select all records where ename may be any no of character but it should end with ‘R’.**select * from emp where ename like'%R';

**21.Count MGR and their salary in emp table.**select count(MGR),count(sal) from emp;

**22.In emp table add comm+sal as total sal .**select ename,(sal+nvl(comm,0)) as totalsal from emp;

**23.Select any salary <3000 from emp table.**select * from emp where sal> any(select sal from emp where sal<3000);

**24.Select all salary <3000 from emp table.**select * from emp where sal> all(select sal from emp where sal<3000);

**25.Select all the employee group by deptno and sal in descending order.**select ename,deptno,sal from emp order by deptno,sal desc;

**26.How can I create an empty table emp1 with same structure as emp?**Create table emp1 as select * from emp where 1=2;

**27.How to retrive record where sal between 1000 to 2000?**Select * from emp where sal>=1000 And sal<2000

**28.Select all records where dept no of both emp and dept table matches.**select * from emp where exists(select * from dept where emp.deptno=dept.deptno)

**29.If there are two tables emp1 and emp2, and both have common record. How can I fetch all the recods but common records only once?**(Select * from emp) Union (Select * from emp1)

**30.How to fetch only common records from two tables emp and emp1?**(Select * from emp) Intersect (Select * from emp1)

**31. How can I retrive all records of emp1 those should not present in emp2?**(Select * from emp) Minus (Select * from emp1)

**32.Count the totalsa deptno wise where more than 2 employees exist.**SELECT deptno, sum(sal) As totalsal

FROM emp

GROUP BY deptno

HAVING COUNT(empno) > 2

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